asked 62.1k views
2 votes
100 points

Factor -2 bk2 + 6 bk - 2 b .

-2b(k 2 + 3k + 1)
-2b(k 2 - 3k + 1)
-2b(k 2 - 3k - 1)

1 Answer

3 votes

Answer:

The factorization of -2bk^2 + 6bk - 2b is -2b(k^2 + 3k + 1).

Explanation:

The factorization of -2bk^2 + 6bk - 2b is -2b(k^2 + 3k + 1).

answered
User Linar
by
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