asked 36.6k views
1 vote
N

50°
AOMN~ ARPQ
Find 0.
M
Ө
0 = [?]°
<
P
70°
R

N 50° AOMN~ ARPQ Find 0. M Ө 0 = [?]° < P 70° R-example-1
asked
User Ether
by
8.3k points

1 Answer

2 votes

Answer:

60°

Explanation:

In similar triangles, the corresponding angles are congruent.

O = R

O = 70°

In ΔOMN,

∠O + ∠M + ∠N = 180 {Angle sum property of triangle}

70 + 50 + Ф = 180

120 + Ф = 180

Subtract 120 from both sides,

Ф = 180 - 120

Ф = 60°

answered
User Sascha Gehlich
by
9.0k points
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