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100 Points! Algebra question. Photo attached. Find the exact value of the expression. Please show as much work as possible. Thank you!

100 Points! Algebra question. Photo attached. Find the exact value of the expression-example-1

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Answer:

Explanation:

To find the exact value of sin(-165 degrees), we can use the trigonometric identity:

sin(-θ) = -sin(θ)

Since sin(165 degrees) is positive, sin(-165 degrees) will be negative. Therefore:

sin(-165 degrees) = -sin(165 degrees)

Now, let's calculate the exact value of sin(165 degrees). We can use the fact that sin(180 degrees - θ) = sin(θ) and sin(θ) = sin(180 degrees + θ). Therefore:

sin(165 degrees) = sin(180 degrees - 15 degrees) = sin(15 degrees)

To find the exact value of sin(15 degrees), we can use the half-angle formula:

sin(θ/2) = sqrt((1 - cosθ)/2)

Let's calculate it:

θ = 15 degrees

cosθ = cos(15 degrees)

Using the half-angle formula:

sin(15 degrees) = sqrt((1 - cos(30 degrees))/2)

Now, we need to calculate cos(30 degrees). We know that cos(30 degrees) = sqrt(3)/2. Substituting this value:

sin(15 degrees) = sqrt((1 - sqrt(3)/2)/2)

To simplify this expression further, we can rationalize the denominator:

sin(15 degrees) = sqrt(2 - sqrt(3))/2

Finally, substituting this value into the equation for sin(-165 degrees):

sin(-165 degrees) = -sin(165 degrees) = -sqrt(2 - sqrt(3))/2

So, the exact value of sin(-165 degrees) is -sqrt(2 - sqrt(3))/2.

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