Question

an inductor with l = 9.85 mh is connected across an ac source that has voltage amplitude 40.0 v. You may want to review (Pages 1023 -1028) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An inductor in an ac circuit Part A What is the phase angle ф for the source voltage relative to the current? Express your answer with the appropriate units.

Answer 1

The phase angle 'Φ' for the source voltage relative to the current in the inductor is 90°.

Step-by-step explanation:

When a sinusoidal voltage is applied to an inductor, the voltage leads the current by one-fourth of a cycle, or by a 90° phase angle. In this case, the inductor has an inductance of 9.85 mH and is connected to an AC source with a voltage amplitude of 40.0 V.

The phase angle 'Φ' refers to the phase difference between the source voltage and the current. Since the voltage leads the current in an inductor by a 90° phase angle, the phase angle 'Φ' is equal to 90° in this scenario.

Answer 2

The phase angle for the source voltage relative to the current in this problem is 90°.

Step-by-step explanation:

When a sinusoidal voltage is applied to an inductor, the voltage leads the current by one-fourth of a cycle, or by a 90° phase angle.

In this case, the inductor has an inductance value of 9.85 mH and is connected to an AC source with a voltage amplitude of 40.0 V.

Therefore, the phase angle φ for the source voltage relative to the current is 90°.