Question

Calculate the mass defect of 19 9f. use 18.9984 amu as the actual mass of 19 9f.

Answer 1

To calculate the mass defect of an isotope, subtract its actual mass from the sum of the masses of its individual particles.

Step-by-step explanation:

The mass defect of an atom is the difference between its actual mass and the sum of the masses of its individual particles (protons, neutrons, and electrons). To calculate the mass defect of an isotope, you can subtract its actual mass from the sum of the masses of its individual particles.

In this case, the mass defect of 19 9F can be calculated as follows:

Mass defect = [(0.9184 x 19.9924 amu) + (0.0047 x 20.9940 amu) + (0.0769 x 21.9914 amu)] - 18.9984 amu

= (18.36 + 0.099 + 1.69) amu - 18.9984 amu

= 0.0916 amu

Answer 2

The mass defect of 19F is -1.1516 amu.

Step-by-step explanation:

The mass defect of 199F can be calculated by finding the difference between the actual mass of 199F and the sum of the masses of its protons, neutrons, and electrons. The actual mass of 199F is given as 18.9984 amu. Using the provided information, we have:

(0.9184 × 19.9924 amu) + (0.0047 × 20.9940 amu) + (0.0769 × 21.9914 amu) = (18.36 + 0.099 + 1.69) amu = 20.15 amu

The mass defect is then calculated as the difference between the actual mass and the calculated mass:

Mass defect = 18.9984 amu - 20.15 amu = -1.1516 amu

Hence, the mass defect of 199F is -1.1516 amu.