Question

Question one

Let F be a Boolean function defined by the following Boolean expression:
F = (¬A ∧ ¬B ∧ ¬C ∧ D) ∨ (¬A ∧ B ∧ C ∧ D) ∨ (A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ ¬B ∧ C ∧ D) ∨ (A ∧ ¬B ∧ ¬C ∧ ¬D)
Where A, B, C, and D are Boolean variables.
a) Construct a truth table for F.
b) Find the minimal sum-of-products form of F using Quine-McCluskey method.
c) Using Boolean algebra, simplify the Boolean expression of F and state the simplified Boolean expression in terms of the three variables A, B, and C.

Answer 1

a) The truth table for F is as follows:

A B C D F

0 0 0 0 1

0 0 0 1 0

0 0 1 0 0

0 0 1 1 1

0 1 0 0 0

0 1 0 1 1

0 1 1 0 1

0 1 1 1 0

1 0 0 0 0

1 0 0 1 1

1 0 1 0 1

1 0 1 1 0

1 1 0 0 1

1 1 0 1 0

1 1 1 0 0

1 1 1 1 1

b) Using the Quine-McCluskey method, we can find the minimal sum-of-products form of F:

F = ¬A ∧ ¬B ∧ D ∨ ¬A ∧ C ∧ D ∨ A ∧ B ∧ ¬C ∧ D ∨ A ∧ ¬B ∧ C ∧ D

c) Using Boolean algebra, we can simplify the Boolean expression of F as follows:

F = (¬A ∧ ¬B ∧ D) ∨ (¬A ∧ C ∧ D) ∨ (A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ ¬B ∧ C ∧ D)

= (¬A ∧ (¬B ∧ D ∨ C ∧ D)) ∨ (A ∧ (B ∧ ¬C ∧ D ∨ ¬B ∧ C ∧ D))

= (¬A ∧ (¬B ∨ C) ∧ D) ∨ (A ∧ ((B ∧ ¬C) ∨ (¬B ∧ C)) ∧ D)

= (¬A ∧ ¬B ∧ C ∧ D) ∨ (¬A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ B ∧ C ∧ D) ∨ (A ∧ ¬B ∧ ¬C ∧ D)

Therefore, the simplified Boolean expression of F in terms of the three variables A, B, and C is:

F = (¬A ∧ ¬B ∧ C ∧ D) ∨ (¬A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ B ∧ C ∧ D) ∨ (A ∧ ¬B ∧ ¬C ∧ D)

Explanation: