asked 85.8k views
2 votes
In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse. If a=8.8 meters and c=10 meters, what is the perimeter? If necessary, round to the nearest tenth.

2 Answers

6 votes

Answer:

The answer is 23.5m to 1 d.p

Explanation:

c²=a²+b²

b²=c²-a²

b²=10²-8.8²

b²=100-77.44

b²=22.56

√b²=√22.56

b=4.7m

Perimeter =a+b+c

P=8.8+4.7+10

P=23.5

P=23.5m to 1 d.p

answered
User Aayush Mahajan
by
7.3k points
5 votes

Answer:

23.6 m

Explanation:

In a right-angled triangle, a ² + b ² = c ²

b² = 10² - 8.8²

100 - 77.44

b = 4.75

perimeter = 4.75 + 8.8 + 10 = 23.55 = 23.6 m to nearest tenth

answered
User Grolschie
by
7.4k points

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