Answer:
Question 56 is C.
Question 57 is A.
Explanation:
For the first question, notice how PQSR is a square (despite not looking like one). This mean RS is also 6 (all sides of a square is equal) and ST is 6 as well (12-6). Now we can find the area of the square and the triangle: 6*6 = 36 cm^2 and (6*6)/2 = 18 cm^2. Then, we can add the two areas together, which is 36 cm^2 + 18 cm^2 = 54 cm^2.
For the second question, we have two approaches: A) Enclose the shape then subtract additional area, or B) Separate the shape into three shapes and find them respectively. I am going to show you the first method. Imagine that this entire shape is an rectangle with the dimensions 7cm x 12cm (3+6+3). The enclosed area will be 84 cm^2. Then, we have to subtract the 5cm x 6cm rectangle from the 84 cm^2, because that's an additional area that does not exist. The final answer will be 84 cm^2 - 30 cm^2 = 54 cm^2.