Answer:
1.43 mol of H2
Step-by-step explanation:
create the balanced equation:
2Al +6HCl to 2AlCl3 + 3H2
from the equation you can see that 2 mols of Al react with 3 mols of H2. so if you have .95 mols of H2 it is (0.95 mol Al)x(3 mol H2/ 2 mol Al)= 1.43 mol of H2