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Consider the following reversible reaction

What is the equilibrium constant expression for the given system?

Consider the following reversible reaction What is the equilibrium constant expression-example-1
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User Wensveen
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4 votes

Answer:

The answer is D - Keq = [H2]^2 × [O2]

[2]^2

Step-by-step explanation:

The equilibrium constant (Keq), is a quantitative measure of the position of equilibrium in a chemical reaction. It is defined by the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants.

For a general chemical reaction:

aA+bB + CC+dD

Explanation: The equilibrium constant expression is given by:

Keq = [C]^c x [D]^d

[A]^a x [B]^b

Where [A], [B], [C], and [D] represent the molar concentrations of the species A, B, C, and D, respectively. The coefficients a, b, c, and d represent the stoichiometric coefficients of the balanced equation.

The given reaction is 2H2O(g) ↔ 2H2(g) + O2(g)

The equilibrium constant expression for the given system can be expressed as follows:

Keq = [H2]^2 × [O2]

[2]^2

Where:

[H2] represents the molar concentration of hydrogen gas (H2).

[O2] represents the molar concentration of oxygen gas (O2).

[H2O] represents the molar concentration of water vapor (H2O).

The equilibrium constant expression for the given system can be expressed as follows: Keq = [H2]^2 × [O2]

[2]^2

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User Svenningsson
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6 votes

Answer:

Step-by-step explanation:

a

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User SiriusBits
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