Final answer:
Among the given mercury isotopes, 190 Hg is the most likely to undergo electron capture, as it has the lowest neutron-to-proton ratio, indicating it is the most proton-rich and thereby most suitable for this decay mode to attain a more stable state.
Step-by-step explanation:
To predict which nuclide is most likely to undergo electron capture, we should look at the neutron-to-proton (n:p) ratio and stability considerations based on atomic number. Nuclides tend to undergo electron capture when their neutron-to-proton ratio is too low, which typically happens in proton-rich nuclei.
Electron capture often occurs in nuclides with atomic numbers lower than 83, and since the choices are all mercury (Hg) isotopes with an atomic number of 80, they all are potential candidates for electron capture. However, specific isotope stability will vary based on neutron count.
Among the given choices for mercury isotopes:
190 Hg has a mass number of 190 and an atomic number of 80, resulting in 110 neutrons and a n:p ratio of 1.375.
195 Hg has a mass number of 195 and an atomic number of 80, resulting in 115 neutrons and a n:p ratio of 1.4375.
200 Hg has a mass number of 200 and an atomic number of 80, resulting in 120 neutrons and a n:p ratio of 1.5.
205 Hg has a mass number of 205 and an atomic number of 80, resulting in 125 neutrons and a n:p ratio of 1.5625.
Determining the most likely to undergo electron capture involves identifying the isotope with the lowest neutron-to-proton ratio, as this condition tends to favor proton-rich nuclides that are more likely to 'absorb' an electron to increase their neutron count and move towards a more stable configuration. Considering this, 190 Hg is the most likely to decay by electron capture since it has the lowest n:p ratio among the given isotopes, which is below the stability line for its atomic number.