Step-by-step explanation:
First, you need to balance the equation:
N2 + 3 H2 ====> 2 NH3
so three moles of H2 result in 2 moles of NH3
ratio of 3:2
How many moles of NH3 is 36.5 gm ??
Using periodic table NH3 mole weight = 14.007 + 3*1.008 =17.031 g/mole
36.5 g / 17.031 g/mole = 2.14 moles of NH3
Using the ratios above 3/2 = x / 2.14 shows x = 3.21 moles of H2 needed