Question

a rocket engine consumes 450 kg of fuel per minute. if the exhaust speed of the ejected fuel is 5.2 km/s, what is the thrust of the rocket?

Answer 1

The thrust of a rocket consuming 450 kg of fuel per minute with an exhaust speed of 5.2 km/s is 39000 newtons (N).

Step-by-step explanation:

The thrust of a rocket is calculated using the equation thrust = rate of fuel consumption × exhaust velocity. Given that the rocket engine consumes 450 kg of fuel per minute and the exhaust speed of the ejected fuel is 5.2 km/s, we can compute the thrust as follows:

• Convert the exhaust velocity from km/s to m/s: 5.2 km/s = 5200 m/s
• Convert the rate of fuel consumption from kg/minute to kg/second: 450 kg/minute = 7.5 kg/second
• Calculate the thrust: Thrust = 7.5 kg/s × 5200 m/s = 39000 N

Therefore, the thrust of the rocket is 39000 newtons (N).

Answer 2

The thrust of the rocket is 2.34 × 10^6 Newtons.

Step-by-step explanation:

The thrust of a rocket can be calculated using the formula:

Thrust = (Mass Flow Rate) × (Exhaust Speed)

Given that the rocket engine consumes 450 kg of fuel per minute and the exhaust speed of the ejected fuel is 5.2 km/s, we can calculate the thrust as follows:

Thrust = (450 kg/min) × (5.2 km/s)

Converting the units to SI units:

Thrust = (450 kg/min) × (5.2 × 10^3 m/s)

Thrust = 2.34 × 10^6 N

Therefore, the thrust of the rocket is 2.34 × 10^6 Newtons.