Question

How many molecules are in 75.0 g of
diphosphorus pentoxide?

Answer 1

Therefore , \[0.528mol \times 6.022 \times {10^{23}}mo{l^{ - 1}} = 3.179 \times {10^{23}}\] molecules. Hence, \[3.179 \times {10^{23}}\] molecules are in \[75.0g\] of diphosphorus pentoxide \[{P_2}{O_5}\] .

Step-by-step explanation:

I hope this helps because I have no idea what the hell this is lol.