Question

a ruby laser emits an intense pulse of light that lasts a mere 20 ns . the light has a wavelength of 690 nm, and each pulse has an energy of 400 mj .

Answer 1

The difference in energy between the initial and final states corresponding to the emission of red light from a ruby laser is 2.853 x 10⁻¹⁹ J.

Step-by-step explanation:

The subject of this question is Physics and it is targeted towards High School students.

The question is asking about the difference in energy between the initial and final states corresponding to the emission of red light from a ruby laser.

To find the difference in energy, we need to use the equation E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10⁻³⁴ J s), c is the speed of light (3.0 x 10⁸ m/s), and λ is the wavelength of the light.

We can calculate the energy difference by substituting the given wavelength of 694.3 nm into the equation:

E = (6.626 x 10⁻³⁴ J s)(3.0 x 10⁸ m/s) / (694.3 x 10⁻⁹ m)

E = 2.853 x 10⁻¹⁹ J