Question

A hemisphere-shaped mole has a diameter of 5.7 millimeters and a surface area of about 51 square millimeters. The radius of the mole doubles. Estimate the new surface area of the mole. Round your answer to the nearest whole number.

Answer 1

The surface area of a hemisphere is given by the formula:

SA = 2πr^2

where r is the radius of the hemisphere.

The diameter of the mole is 5.7 millimeters, so the radius is 2.85 millimeters. The surface area of the mole is about 51 square millimeters.

If the radius doubles, the new radius will be 5.7 millimeters, and the new surface area of the mole will be:

SA = 2π(5.7)^2 = 204 square millimeters

Rounding to the nearest whole number, the new surface area of the mole is 204 square millimeters.