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what is the equation of the line that is perpendicular to the line 7-5x=4 and passes through the point (5,8)

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User Agbinfo
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8.4k points

1 Answer

3 votes

Answer:

b = -6 + 10/7 = -32/7

Explanation:

So any line can be defined with a slope and a point. The line is perpendicular to y = 7/5x + 6 which has a slope of 7/5, but we want to find the slope of the line perpendicular. So we take the opposite inverse of 7/5, which is -5/7. So -5/7 is going to be the slope of the line.

Plug this in to the formula for a line:

y = -5/7x + b.

Now we'll solve for b. We were given that it passes through the point (2, -6) meaning that when x = 2, y = -6.

Plug this in and solve for b.

-6 = -5/7 (2) + b

-6 = -10/7 + b

b = -6 + 10/7 = -32/7

answered
User KateMak
by
8.3k points

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