Question

Using your H-W equation, calculate the following. The value of q is 0.28; there is then a value to p2; what does the information tell us about this answer?

Question options:

Heterozygous individuals are more common


Both the dominant and recessive alleles are equally dispersed in this population.


Homozygous dominant individuals are more common


Homozygous recessive individuals are more common

Answer 1

The Hardy-Weinberg (H-W) equation is used to describe the frequencies of alleles in a population. It states that the frequency of the dominant allele (p2) can be calculated with the formula p2 = q2 + 2pq, where q is the frequency of the recessive allele. In the given example, the value of q is 0.28. Consequently, the value of p2 is 1.1936 (0.282 + 2*0.28*0.28). This tells us that in this population, homozygous dominant individuals (who have two copies of the dominant allele) are more common than homozygous recessive individuals (who have two copies of the recessive allele).

Step-by-step explanation: