Question

A rectangular container is 6 cm wide and 9 cm long, and contains water to a depth of 7 cm. An object is placed in

the water and the water rises 3,5 cm. What is the volume of the object?

Answer 1

189 cm³

Explanation:

Volume of the object equals the volume of water increased. To find the volume of the water that increased, subtract the volume of water after increasing from the volume of water before increasing.

Volume of the rectangular container before water rise:

l = 9 cm ; w = 6 cm ; h = 7 cm

`\boxed{\text{\bf Volume of rectangular prism = l*w*h}}`

V₁ = 9 * 6 * 7

= 378 cm³

Volume of the container after water rise:

l = 9 cm ; w = 6 cm ; h = 7 + 3.5 = 10.5 cm

V₂ = 9 * 6 * 10.5

= 567 cm³

Volume of the water that increased = V₂ - V₁

= 567 - 378

= 189 cm³

Volume of the object = 189 cm³