Question

Pls someone help me!!

Answer 1

C=46

using simultaneous equation method to find the minimum values of x and y. As Y is equal in both equations you can cancel them out and minus x from 4x and 24 -15 leaving 3x=9 , x=3, placing this value into one of the equation such as 3+3y = 15 then solving finds y=4 . use these values to find C

Answer 2

minimum value of C is 46
Explanation:
A sketch of the constraints is advised.
Sketch
4x + 3y = 24
with intercepts at (0, 8) and (6, 0)
x + 3y = 15
with intercepts at (0, 5) and (15, 0)
The solutions to both are above the lines.
Solve 4x + 3y = 24 and x + 3y = 15 simultaneously to obtain point of intersection at (3, 4)
Then the coordinates of the vertices of the feasible region are at
(0, 8), (3, 4) and (15, 0)
Evaluate the objective function at each vertex
(0, 8) → C = (6 × 0) + (7 × 8) = 0 + 56 = 56
(3, 4) → C = (6 × 3) + (7 × 4) = 18 + 28 = 46
(15, 0) → (6 × 15) + (7 × 0) = 90 + 0 = 90
The minimum value of C is 46 when x = 3 and y = 4