Question

The phasor corresponding to the signal v(t) = 21 cos(4t – 12°) V is 21∠( (Click to select) °) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees

Answer 1

The phasor corresponding to the signal v(t) = 21 cos(4t – 12°) V is:

21 ∠(-12°) V

Note that the angle is negative since the cosine function has a phase shift of -12°. To ensure that the angle is within the range of -180° to 180°, we can add or subtract multiples of 360°. However, in this case, since the angle is already within the desired range, we do not need to add or subtract any multiples of 360°.

Step-by-step explanation: