Answer:
Explanation:
Based on the given information, we can visualize the cracker as a cylinder with two circular faces, where the diameter of the cylinder is 16mm, the diameter of the hole is 8mm, and the length of the cylinder is 18mm.
To find the volume of the cracker, we can use the formula for the volume of a cylinder:
V = πr^2h
where V is the volume, r is the radius of the cylinder, and h is the height or length of the cylinder.
First, we need to find the radius of the cylinder, which is half of the diameter. So, the radius of the cylinder is:
r = 16mm/2 = 8mm
Next, we can find the volume of the cylinder by plugging in the values we have:
V = π(8mm)^2(18mm)
V = 3.14 x 64mm^2 x 18mm
V = 36288.64mm^3
However, we also need to subtract the volume of the hole in the middle of the cylinder. The hole can be visualized as another cylinder with the same length as the outer cylinder, but with a smaller radius of 4mm (half of the hole diameter). So, the volume of the hole is:
V_hole = π(4mm)^2(18mm)
V_hole = 3.14 x 16mm^2 x 18mm
V_hole = 9043.52mm^3
Therefore, the volume of the cracker (without the hole) is:
V_cracker = V - V_hole
V_cracker = 36288.64mm^3 - 9043.52mm^3
V_cracker = 27245.12mm^3
So, the volume of the entire cracker (including the hole) is 27,245.12 cubic millimeters.