Question

C

2 mm
9 mm
What is the length of the hypotenuse? If
necessary, round to the nearest tenth.
C =
millimeters

Answer 1

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=√(a^2 + o^2) \end{array} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{2}\\ o=\stackrel{opposite}{9} \end{cases} \\\\\\ c=√( 2^2 + 9^2)\implies c=√( 4 + 81 ) \implies c=√( 85 )\implies c\approx 9.2`