Question

Calculate the molality of potassium hydroxide (molar mass 56 g/mol) in a solution that which contain 112 g of potassium hydroxide in 0.500 kg of water.

Answer 1

4 mol/kg

Explanation :

potassium hydroxide = KOH

1.

get moles of solute =

mass of solute KOH ÷ molar mass of KOH

moles of potassium hydroxide =

112 g / 56 g/mol = 2 mol

2.

get Molality =

moles of solute ÷ Mass of solvent

Mass of solvent = 0.500 kg

Molality = 2 mol / 0.500 kg = 4 mol/kg

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