Question

the mass flow rate, specific heat, and inlet temperature of the tube-side stream in a double-pipe, parallel-flow heat exchanger are 2700 kg/h, 2.0 kj/kg.k, and 120c, respectively. the mass flow rate, specific heat and inlet temperature of the other stream are 1800 kg/h, 4.0 kj/kg.k, and 20c, respectively. the heat transfer area and overall heat transfer coefficient are 0.5 m2 and 2.0 kw/m2 .k, respectively. find the outlet temperature of both streams in steady operation using

Answer 1

The outlet temperature of both streams in a parallel-flow heat exchanger can be found using the energy balance equation. Given the mass flow rates, specific heats, and inlet temperatures, we can calculate the outlet temperatures using the equation. The outlet temperatures for both streams are 53.33 °C.

Step-by-step explanation:

The outlet temperature of both streams in a parallel-flow heat exchanger can be found using the energy balance equation.

Using the equation:

(m1 * Cp1 * (T1,in - T1,out)) = (m2 * Cp2 * (T2,out - T2,in))

where:

• m1 and m2 are the mass flow rates of the tube-side and other streams
• Cp1 and Cp2 are the specific heats of the tube-side and other streams
• T1,in and T2,in are the inlet temperatures of the tube-side and other streams
• T1,out and T2,out are the outlet temperatures of the tube-side and other streams

Given the values:

• m1 = 2700 kg/h
• m2 = 1800 kg/h
• Cp1 = 2.0 kJ/kg.K
• Cp2 = 4.0 kJ/kg.K
• T1,in = 120 °C
• T2,in = 20 °C

We can substitute these values into the equation and solve for the outlet temperatures:

(2700 * 2.0 * (120 - T1,out)) = (1800 * 4.0 * (T2,out - 20))

Simplifying this equation, we get:

T1,out = 53.33 °C

T2,out = 53.33 °C