asked 6.7k views
5 votes
Blake recorded the high temperatures each day for a month in two different cities.

For City A, the mean high temperature was 59°F with a mean absolute deviation of 3.2.
For City B, the mean high temperature was 71°F with a mean absolute deviation of 2.9.
Compare the difference of the means in terms of the mean absolute deviations

asked
User Mculhane
by
8.1k points

1 Answer

5 votes

Answer:

City B is significantly higher than in City A.

Explanation:

To compare the difference of the means in terms of the mean absolute deviations, we can use the concept of standard deviation units. We divide the difference of the means by the average of the mean absolute deviations of the two cities:

D = (71 - 59) / ((3.2 + 2.9) / 2)

D = 12 / 3.05

D ≈ 3.934

The value of D tells us that the difference of the means between the two cities is almost 4 standard deviation units, which is a large difference. This means that the mean high temperature in City B is significantly higher than in City A.

answered
User Huupke
by
8.1k points
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