Question

A 11.5 mL sample of gas at 415.0 K

is cooled to 200.0 K. What is the
new volume of the gas assuming
the amount of gas and pressure are
constant?
V = [?] mL
Volume (mL)

Answer 1

5.54mL = V2

Step-by-step explanation:

V1 = 11.5mL

T1 = 415k

T2 = 200k

V2 = ?

`(V1)/(T1 ) = (V2)/(T2 )` so this means
`(11.5)/(415) = (V2)/(200 )` then you cross multiply

(11.5)(200) = (415)(V2)

2300 = 415 x V2

then you have to divide

`(2300)/(415) = (415+V2)/(415)`

then you cross out the 415 from the top and bottom of second part so its not there so it would be
`(2300)/(415 ) = V2`

then divide

`(2300)/(415 ) = V2` so V2 = 5.54mL (mL bc thats the only volume in the equation)