Question

Trace coding below

p = 2

q = 4

while p < q

output "Adios"

r = 1

while r < q

output "Adios"

r = r + 1

endwhile

p = p + 1

endwhile

Answer 1

In this code, we start by initializing the variable p to 2 and the variable q to 4. Then we enter a while loop that runs as long as p is less than q. Inside the loop, we output the string "Adios".

Next, we initialize the variable r to 1 and enter another while loop that runs as long as r is less than q. Inside this loop, we also output the string "Adios". After each iteration of this inner loop, we increment r by 1.

Once the inner loop completes, we exit back to the outer loop, and increment p by 1. The program will continue running in this way until p is no longer less than q.

The output of this program will be two lines of "Adios" printed multiple times, depending on the value of q. Since p is always less than q, the outer loop will always run at least once, and the inner loop will run q-1 times. So, the output will be:

Adios

Adios

Adios

Adios

Note that the value of p and q do not change during the execution of the program, so the output will always be the same.

Step-by-step explanation: