Question

Find the real zeros of the polynomial function

f
(
x
)
=
(
x
+
7
)
(
9
x^2
+
5
x
+
4
)
.

Answer 1

x = -7

Explanation:

Since f(x) =
`(x+7)(9x^2+5x+4)`, we can set both equal to 0.

x + 7 = 0 will give us x = -7.

Now, in the second equation, we will plug into the quadratic formula, when we do that, the number inside the discriminator (which is the square root) is -119. A square root of a negative number is imaginary and not real.

Therefore, the only real zero of the polynomial is -7