The given set contains the square roots of 9, 36, 50, and 121. To determine the approximate value of the irrational number included in the set, we need to evaluate each of these square roots.
√9 = 3 √36 = 6 √50 = approximately 7.07 (rounded to two decimal places) √121 = 11
Therefore, the approximate value of the irrational number included in the set is 7.1, which is the approximate value of √50.
We can use a calculator to determine the approximate value of a square root. From the calculation, √50 = 7.07107..., which can be rounded to 7.1 to two decimal places. So, option 2, 7.1, is the correct answer.