Question

What is the predominant form of ethylenediamine at pH 6.441 and pH 9.375? Ethylenediamine has pKb values of 4.072 (pKb1) and 7.152 (pKb2).

Answer 1

The predominant form of ethylenediamine at pH 6.441 and pH 9.375 can be determined by comparing the pH values to the pKb values of ethylenediamine.

Step-by-step explanation:

The predominant form of ethylenediamine at pH 6.441 and pH 9.375 can be determined by comparing the pH values to the pKb values of ethylenediamine. The pKb values for ethylenediamine are 4.072 (pKb1) and 7.152 (pKb2). The pH value of 6.441 is lower than both pKb values, so the predominant form of ethylenediamine at this pH is the basic form (BH+). The pH value of 9.375 is higher than both pKb values, so the predominant form at this pH is the conjugate acid form (B).

Answer 2

The predominant form of ethylenediamine at pH 6.441 would be the form with a lower pKa value, which is pKb1. At pH 9.375, the predominant form would be the form with a higher pKa value, which is pKb2.

Step-by-step explanation:

The predominant form of ethylenediamine at pH 6.441 would be the form with a lower pKa value, which is pKb1. At pH 6.441, ethylenediamine would exist primarily in the form of its conjugate acid, which is the protonated form of ethylenediamine. On the other hand, at pH 9.375, the predominant form would be the form with a higher pKa value, which is pKb2. At pH 9.375, ethylenediamine would exist primarily in the form of the deprotonated form of its conjugate acid.