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A 85.0- kgkg person is exposed to 789 radrad of radiation. how many joules did this person absorb?

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User BruceJo
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2 Answers

7 votes

Final answer:

To calculate the amount of energy absorbed by a person exposed to radiation, we can use the formula: Energy (J) = Dose (rad) x Mass (kg) x Conversion factor (J/kg). Given the values provided, the person in question absorbed 669.15 Joules of energy.

Step-by-step explanation:

In this question, the person's weight is given as 85.0 kg and the radiation exposure is given as 789 rad. To calculate the amount of energy absorbed, we can use the formula:

Energy (J) = Dose (rad) x Mass (kg) x Conversion factor (J/kg)

Given that 1 rad = 0.010 J/kg, we can substitute the values into the formula:

Energy (J) = 789 rad x 85.0 kg x 0.010 J/kg

Simplifying the calculation, we find that the person absorbed 669.15 Joules of energy.

answered
User Suppen
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8.0k points
2 votes

Final answer:

The person absorbed a total of 67,065 J of energy from the radiation.

Step-by-step explanation:

In this case, we can use the formula:
Energy absorbed (J) = Dose (rad) x Mass (kg)

Given that the person's mass is 85.0 kg and the dose is 789 rad, we can substitute these values into the formula:
Energy absorbed (J) = 789 rad x 85.0 kg

Therefore, the person absorbed a total of 67,065 J of energy from the radiation.

answered
User Garee
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8.0k points