Question

X^2-8x=20
Pls help I’m failing

Answer 1

x=10 and x=-2

Explanation:

x^2-8x-20=0

x^2-10x+2x-20=0

x(x-10)+2(x-10)=0

(x-10)(x+2)=0

x-10=0 or x+2=0

x=10 or x=-2

Answer 2

Explanation:

No worries, let's see if we can solve this equation together.First, let's rearrange the equation so that it's in standard quadratic form, which is ax^2 + bx + c = 0. In this case, we have:x^2 - 8x = 20Subtracting 20 from both sides, we get:x^2 - 8x - 20 = 0Now, we can solve for x using the quadratic formula:x = (-b ± sqrt(b^2 - 4ac)) / 2aIn this case, a = 1, b = -8, and c = -20. Substituting these values into the quadratic formula, we get:x = (-(-8) ± sqrt((-8)^2 - 4(1)(-20))) / 2(1)Simplifying:x = (8 ± sqrt(144)) / 2x = (8 ± 12) / 2So we have two possible solutions:x1 = (8 + 12) / 2 = 10

x2 = (8 - 12) / 2 = -2Therefore, the solutions to the equation x^2 - 8x = 20 are x = 10 and x = -2.