Final answer:
The frequency of a recessive lethal allele in a large, randomly mating population where homozygotes die before reproducing will remain the same in the next generation. The surviving offspring's genotypes are either AA or Aa since aa individuals die, so the allele frequency stays at 0.20.
Step-by-step explanation:
In a large, randomly mating population with a frequency of an autosomal recessive lethal allele of 0.20, and assuming that all homozygotes die before reproducing, we can predict the frequency of this allele in the next generation. In this scenario, only the wild-type homozygotes (AA) and heterozygotes (Aa) will survive to reproduce. When two heterozygous individuals (Aa) mate, the expected genotypic ratio in their offspring would be 1:2:1 under normal Mendelian inheritance for a single-gene trait with two alleles. However, because aa individuals die before reproducing, the actual observed ratio is 1:2:0.
This pattern of inheritance is referred to as recessive lethal. The recessive allele is lethal in the homozygous form (aa), leading to only three possible genotypes among the surviving offspring: AA and Aa. As a result, half of the surviving offspring will be heterozygous carriers of the allele. The allele frequency remains the same because carriers (Aa) still possess the lethal allele, and it can be passed on to the next generation with the same probability as before. Hence, the frequency of the recessive lethal allele in the next generation will remain at 0.20, assuming there is no other evolutionary force acting on the allele frequency like mutation, migration, or selection for or against heterozygotes.