Question

A jar has five red balls and five blue balls. You have to draw any two balls from the jar. You do not replace the first ball in the jar before drawing the second ball. If the first ball is red and is not replaced in the jar, what is the probability that the second ball is blue?

Answer 1

5/9ths or 0.5556

Explanation:

because you have already removed one red ball, that means that there are 4 red balls and 5 blue balls. Adding the balls together, you have 9 balls. therefore you have a 5/9 chance to pick a blue ball.