Question

Write the equation in standard form for the circle with center (-4, 0) and radius 6./3.

Answer 1

Explanation:

center -4,0

(x- - 4)^2 + (y-0)^2

(x+4)^2 + y ^2

with radius 6/3

(x+4)^2 + y^2 = ( 6/3)^2

(x+4)^2 + y^2 = 4