Answer:
Step-by-step explanation:To solve the quadratic equation 6x²-11x-35= 0, we can use the quadratic formula:
x = (-b ± sqrt(b² - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation.
In this case, we have:
a = 6
b = -11
c = -35
Substituting these values into the quadratic formula, we get:
x = (-(-11) ± sqrt((-11)² - 4(6)(-35))) / 2(6)
Simplifying this expression:
x = (11 ± sqrt(121 + 840)) / 12
x = (11 ± sqrt(961)) / 12
x = (11 ± 31) / 12
So, we have two solutions:
x = (11 + 31) / 12 = 3
and
x = (11 - 31) / 12 = -5/2
Therefore, the solutions to the equation 6x²-11x-35= 0 are x = 3 and x = -5/2.