Question

IF THERE ARE 12 RUNNERS IN A RACE, AND 3 RUNNERS ARE RANDOMLY CHOSEN OUT OF THE 12 FOR DRUG TESTING, HOW MANY DIFFERENT WAYS CAN THESE 3 BE CHOSEN?

Answer 1

we need combination formula:

`(nı)/((n - r)ı * rı)`

"I means !"

so the answer is:

12!/9! × 3! = 440

Answer 2

They can be picked out by performance.
Is it multiple choice?