Question

While grocery shopping, Dylan bought

some apples for $3.50. He also bought
some grapes that cost $1.25 more than
the apples. The combined cost of the
grapes and apples made up 20% of his
total grocery bill. What was the total
amount of Dylan's grocery bill in dollars
and cents?

Answer 1

Dylan's total grocery bill was $41.25

Explanation:

Let the cost of the apples be a. Then, the cost of the grapes is a + 1.25, since the grapes cost $1.25 more than the apples.

The combined cost of the apples and grapes is a + (a + 1.25) = 2a + 1.25.

We know that the combined cost of the apples and grapes is 20% of Dylan's total grocery bill, so we can set up the following equation:

2a + 1.25 = 0.2x

where x is the total cost of Dylan's grocery bill.

To solve for x, we can isolate x on one side of the equation:

2a + 1.25 = 0.2x

2a = 0.2x - 1.25

a = 0.1x - 0.625

We also know that the cost of the apples is $3.50, so we can set up another equation:

a = 3.5

Substituting this into the equation we just found:

3.5 = 0.1x - 0.625

4.125 = 0.1x

x = 41.25

Therefore, Dylan's total grocery bill was $41.25.

Answer 2

Dylan's grocery bill was $41.25.

Explanation:

Let's call the cost of the grapes "g".

We know that the grapes cost $1.25 more than the apples, so we can write:

g = 3.50 + 1.25 = 4.75

The combined cost of the grapes and apples is 20% of Dylan's total grocery bill, so we can write:

3.50 + 4.75 = 0.20x

where x is the total grocery bill.

We can solve for x by simplifying the equation:

8.25 = 0.20x

x = 8.25 / 0.20

x = 41.25

Therefore, the total amount of Dylan's grocery bill was $41.25.