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Answer:
-x³ + 2x + 7
2x^5+x^4-x³+6x²+3x-3
Explanation:
For #10:
(f-g)(x) = f(x) - g(x)
x³-2x+3 - (2x³ + 4x - 4)
For #11:
(f·g)(x) = f(x) * g(x)
(x³+3)(2x²+x-1) = 2x^5+x^4-x³+6x²+3x-3