Question

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How many moles of aluminum are needed to react completely with 213 g Cl2? (CI2:71 g/mol)
2AI + 3CI2 ---> 2AICI3
213g CI2--> mol AI

Answer 1

3 moles of aluminum are needed to react completely with 213 g of Cl2.

Step-by-step explanation:

First, we need to find the number of moles of Cl2 in 213 g.

mass of Cl2 = 213 g

molar mass of Cl2 = 71 g/mol

Number of moles of Cl2 = mass of Cl2/molar mass of Cl2

= 213/71

= 3 moles

Now, from the balanced chemical equation, we know that 2 moles of Al reacts with 3 moles of Cl2 to produce 2 moles of AICI3.

So, to react completely with 3 moles of Cl2, we need (2/3) x 3 = 2 moles of Al.

Therefore, to react completely with 213 g of Cl2, we need 2 moles of Al.

Note:

It is important to use the correct units and molar masses in the calculations to obtain accurate results.