Answer:
The chemical equation for the conversion of glucose to ethanol during fermentation is:
C6H12O6 → 2C2H5OH + 2CO2
From the equation, we can see that for every mole of glucose (C6H12O6) that reacts, two moles of ethanol (C2H5OH) are produced. The molar mass of glucose is 180.16 g/mol, while the molar mass of ethanol is 46.07 g/mol.
Therefore, to calculate the mass of ethanol produced from 500.0 grams of glucose, we need to convert the mass of glucose to moles, then use the mole ratio from the balanced chemical equation to calculate the moles of ethanol produced, and finally convert the moles of ethanol to mass.
Step 1: Convert the mass of glucose to moles
Number of moles of glucose = mass of glucose ÷ molar mass of glucose
Number of moles of glucose = 500.0 g ÷ 180.16 g/mol
Number of moles of glucose = 2.776 mol
Step 2: Use the mole ratio to calculate the moles of ethanol produced
From the balanced equation, 1 mol of glucose produces 2 mol of ethanol
Therefore, 2.776 mol of glucose will produce:
2.776 mol glucose × (2 mol ethanol / 1 mol glucose) = 5.552 mol ethanol
Step 3: Convert moles of ethanol to mass
Mass of ethanol = number of moles of ethanol × molar mass of ethanol
Mass of ethanol = 5.552 mol × 46.07 g/mol
Mass of ethanol = 255.2 g
Therefore, 500.0 grams of glucose will produce 255.2 grams of ethanol during fermentation.
I hope this helps you! :)))
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