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Find the solution(s) of the quadratic equation x 2 squared + 2x - 15=0

2 Answers

3 votes

Answer: -5, 3

Explanation:

Equation:

x² + 2x -15 = 0 The equation is already set =0 so you will factor.

To factor, find 2 numbers that multiply to the last term (-15) but add up to the middle term (+2). Be careful with signs, signs matter

+5 and -3 multiply to -15 but add up to the +2 so these are your factored numbers

put it in factored form

(x+5)(x-3)=0 set each parenthesis =0 to solve for x

x+5 = 0 x-3=0

x= -5 and x=3

answered
User Vijay Kotari
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8.5k points
4 votes
To solve the quadratic equation x^2 + 2x - 15 = 0, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation.

In this case, a = 1, b = 2, and c = -15. Substituting these values into the quadratic formula, we get:

x = (-2 ± sqrt(2^2 - 4(1)(-15))) / 2(1)

Simplifying the expression under the square root, we get:

x = (-2 ± sqrt(64)) / 2

Taking the square root of 64, we get 8:

x = (-2 ± 8) / 2

Simplifying the expression on the right side, we get:

x = (-2 + 8) / 2 or x = (-2 - 8) / 2

x = 3 or x = -5

Therefore, the solutions to the quadratic equation x^2 + 2x - 15 = 0 are x = 3 and x = -5.
answered
User OzzyTheGiant
by
8.6k points

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