Question

Zinc reacts with Hydrochloric Acid in a single replacement reaction. If you have 8 g of of zinc metal, what mass of each product would you produce?

Answer 1

`16.68g ZnCl_2`

`0.2472g H_2`

Step-by-step explanation:

1.)Write equation:

`Zn(aq)+HCl(aq)== > ZnCl_2(aq)+H_2(g)`

2.)Balance:

`Zn(aq)+2HCl(aq)== > ZnCl_2(aq)+H_2(g)`

3.)Convert:

`8g Zn/(1mol Zn)/(65.380g Zn)/(1mol ZnCl_2)/(1mol Zn)/(136.28g ZnCl_2)/(1mol ZnCl_2) =16.68g ZnCl_2`

`8g Zn/(1mol Zn)/(65.380g Zn)/(1 molH_2)/(1molZn)/(2.02g H_2)/(1mol H_2)=0.2472g H_2`

(This does not include sig figs)