Question

Find the volume that 42g of carbon monoxide gas occupies at STP

Answer 1

Step-by-step explanation:

Find the mole weight of CO :

C = 12.011 gm/ mole

O =15.999 gm/mole

total = 28.01 gm /mole

42 gm is then 42 gm / 28.01 gm/mole = 1.5 mole of CO

Gases occupy 22.4 liters per mole at STP

22.4 L / mole * 1.5 mole = 33.6 liters