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An auto body shop receives 70% of its parts from one manufacturer. If parts from the shop are selected at random, what is the probability that the first part not from this manufacturer is the 6th part selected

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User Amitabh
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1 Answer

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Since the auto body shop receives 70% of its parts from one manufacturer, the probability that a part is not from this manufacturer is 30%.

To find the probability that the first part not from this manufacturer is the 6th part selected, we can use the formula for the probability of a specific order of events in a sequence, which is:

P(event 1 and event 2 and ... and event n) = P(event 1) × P(event 2 | event 1) × P(event 3 | event 1 and event 2) × ... × P(event n | event 1 and event 2 and ... and event n-1)

In this case, let event 1 be selecting a part not from the manufacturer, and let event 2 through event 6 be selecting any part in any order. Then, we have:

P(select 6th part not from manufacturer first) = P(not from manufacturer) × P(any part) × P(any part) × P(any part) × P(any part) × P(any part | event 1 and event 2 and event 3 and event 4 and event 5)

Since the events of selecting each part are independent and the probability of selecting any part is the same, we can simplify this expression to:

P(select 6th part not from manufacturer first) = 0.3 × 0.7^5

Calculating this expression gives:

P(select 6th part not from manufacturer first) = 0.3 × 0.16807 = 0.05042

Therefore, the probability that the first part not from this manufacturer is the 6th part selected is approximately 0.05042 or 5.04%.
answered
User Taheem
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