Question

A car travels at a constant speed.

It travels a distance of 146.2 m, correct to 1 decimal place.
This takes 7 seconds, correct to nearest second.
Calculate the upper bound for the speed of the car.​

Answer 1

22.5m/s

Explanation:

• upper bound=higher value of distance /lower value of time
• upper value of distance=146.2+0.05
• =146.25
• lower value of time=7-0.5
• =6.5
• 146.25/6.5
• =22.5m/s

Answer 2

Answer below.

Explanation:

Formula to use:

upper bound of speed = upper bound of distance/lower bound of time

Upper bound of distance = 146.25m

Lower bound of time = 6.5s

Upper bound of speed = 146.25/6.5

= 22.5m/s