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Given vectors A → = 2.0 x ^ − 3.2 y ^ and B → = − 1.2 x ^ + 2.9 y ^ what is the angle between the vector D → = A → − B → and the positive x-axis?

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Okay, let's solve this step-by-step:

1) Given:

A → = 2.0 x ^ − 3.2 y ^

B → = − 1.2 x ^ + 2.9 y ^

Find: Angle between D → = A → − B → and positive x-axis

2) Subtract the vectors to find D →:

D → = 2.0 x ^ − 3.2 y ^ - (− 1.2 x ^ + 2.9 y ^ )

= 2.0 x ^ − 3.2 y ^ + 1.2 x ^ - 2.9 y ^

= 3.2 x ^ − 6.1 y ^

3) To find the angle, we use the inverse tangent ratio of y/x:

Angle = tan−1(−6.1/3.2) = -61.97°

4) Since the angle is in the 4th quadrant, it is measured clockwise from the positive x-axis. So the final angle is 180 - 61.97 = 118.03°

Therefore, the angle between the vector D → = A → − B → and the positive x-axis is 118.03°.

Let me know if you have any other questions!

answered
User Goran Vasic
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