Question

A 393 ml air sample collected at 45°c has a pressure of 688 torr what pressure will the air extert if it is allowed to expand to 491ml at 62°c

Answer in units of torr

Answer 1

This is the combined gas law formula:

(P1V1)/(T1) = (P2V2)/(T2)

where P1 = 688 torr, V1 = 393 ml, T1 = 45°C + 273.15 = 318.15 K, P2 = unknown, V2 = 491 ml, and T2 = 62°C + 273.15 = 335.15 K.

Solving for P2:

P2 = (P1V1T2)/(V2T1)

= (688 torr * 393 ml * 335.15 K) / (491 ml * 318.15 K)

= 821.38 torr

Therefore, the air will exert a pressure of 821.38 torrs when expanded to 491 ml at 62°C.