Question

Find the minimum of four even consecutive natural numbers whose sum is 204?

Answer 1

Let's call the smallest of the four even consecutive natural numbers "x".

Since the numbers are even, we know that the next three even consecutive numbers are x+2, x+4, and x+6.

The sum of these four numbers is 204:

x + (x+2) + (x+4) + (x+6) = 204

Simplifying the left side:

4x + 12 = 204

Subtracting 12 from both sides:

4x = 192

Dividing both sides by 4:

x = 48

So the smallest of the four even consecutive natural numbers is 48.

The next three even consecutive numbers are 50, 52, and 54.

Therefore, the minimum of the four even consecutive natural numbers whose sum is 204 is 48.

Answer 2

48

Explanation:

natural even numbers have a difference of 2 between them

let n be the minimum number , then the next 3 are

n + 2, n + 4, n + 6

sum the 4 numbers and equate to 204

n + n + 2 + n + 4 + n + 6 = 204

4n + 12 = 204 ( subtract 12 from both sides )

4n = 192 ( divide both sides by 4 )

n = 48

the 4 numbers are then 48, 50, 52, 54

with the minimum being 48